Solved the two questions of the JavaScript

1. Get the max elements from the given array
2. Get the median elements from the given array

Author: Devendra Parmar

October/GetTheMaxElementFromTheProvidedArray.js

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+// Write a JavaScript program to get the n maximum elements from the provided array. If n is greater than or equal to the provided array's length, return the original array (sorted in descending order).
+
+const maxElem = (arr, n = 1) => {
+  return [...arr].sort((a, b) => b - a).slice(0, n);
+};
+
+const prompt = require("prompt-sync")();
+
+var size = parseInt(prompt("Enter The Array Size : "));
+
+var arr = [];
+
+console.log("Enter Array Elements : ");
+for (let i = 0; i < size; i++) {
+  var elem = parseInt(prompt(`[${i}] : `));
+  arr.push(elem);
+}
+
+var ele = parseInt(prompt("Enter How Many Element You Want Find : "));
+
+var ans = maxElem(arr, ele);
+
+console.log(ans);

October/GetTheMedianOfArray.js

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+// Write a JavaScript program to get the median of an array of numbers.
+
+// Note: Find the middle of the array, use Array.sort() to sort the values. Return the number at the midpoint if length is odd, otherwise the average of the two middle numbers.
+
+const midElem = (arr) => {
+  const mid = Math.floor(arr.length / 2),
+    num = [...arr].sort((a, b) => a - b);
+  return arr.length % 2 !== 0 ? num[mid] : (num[mid - 1] + num[mid]) / 2;
+};
+
+const prompt = require("prompt-sync")();
+
+var size = parseInt(prompt("Enter Array Size : "));
+
+var arr = [];
+
+console.log("Enter Array Elements : ");
+for (let i = 0; i < size; i++) {
+  var elem = parseInt(prompt(`[${i}] : `));
+  arr.push(elem);
+}
+
+var mid = midElem(arr);
+
+console.log(mid);