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0.MATH.cpp
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147 lines (146 loc) · 4.45 KB
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#include <iostream>
#include <vector>
#include <cmath>
#include <complex>
// DONE
// GCD, 분할 정복을 이용한 거듭제곱 (수, 행렬), 고속 푸리에 변환(FFT)
// TODO
// 뤼카의 정리, 폴라드 로 알고리즘, 확장 유클리드 알고리즘
int gcd(int a, int b) {
if(a % b == 0) {
return b;
}
else {
return gcd(b, a % b);
}
}
int A, B, C;
int multiplication(int x, int n) {
if(n == 0) {
return x;
}
else{
int square = ((unsigned long long) x * (unsigned long long) x) % C;
return multiplication(square, n - 1);
}
}
int NumberPow() {
std::cin >> A >> B >> C;
int m = std::log(B) / std::log(2);
unsigned long long ret = 1;
for(int i = m ; i >= 0 ; i--) {
if( (B & ((unsigned long long)1 << i)) == ((unsigned long long)1 << i)) {
//std::cout << i << "\n";
ret *= (unsigned long long) multiplication(A, i);
ret %= C;
}
}
std::cout << ret << "\n";
}
int n;
std::vector<std::vector<int>> matrixMultiplication(std::vector<std::vector<int>> A, std::vector<std::vector<int>> B) {
std::vector<std::vector<int>> C(n, std::vector<int>(n, 0));
for(int i = 0 ; i < n ; i++) {
for(int j = 0 ; j < n ; j++) {
int sum = 0;
for(int k = 0 ; k < n ; k++) {
sum += (A[i][k] * B[k][j]);
}
C[i][j] = sum;
}
}
return C;
}
int MatrixPow() {
unsigned long long B;
std::cin >> n >> B;
std::vector<std::vector<int>> A(n, std::vector<int>(n, 0));
for(int i = 0 ; i < n ; i++) {
for(int j = 0 ; j < n ; j++) {
std::cin >> A[i][j];
}
}
int m = std::log(B) / std::log(2);
std::vector<std::vector<std::vector<int>>> MT (m + 1, std::vector<std::vector<int>>(n, std::vector<int>(n, 0)));
for(int i = 0 ; i <= m ; i++) {
if(i == 0) {
MT[i] = A;
}
else {
MT[i] = matrixMultiplication(MT[i - 1], MT[i - 1]);
}
}
std::vector<std::vector<int>> ret(n, std::vector<int>(n, 0));
for(int i = 0 ; i < n ; i++) {
for(int j = 0 ; j < n ; j++) {
if(i == j) {
ret[i][j] = 1;
}
}
}
for(int i = 0 ; i <= m ; i++) {
if( (B & ((unsigned long long)1 << i)) == ((unsigned long long)1 << i) ) {
ret = matrixMultiplication(ret, MT[i]);
}
}
}
const long double PI = acos(-1.L);
unsigned long long bitconvert(unsigned long long n, unsigned long long k) {
unsigned long long ret = 0;
for(unsigned long long i = 0 ; i < k ; ++i) {
ret |= ( (n >> i) & (unsigned long long) 1 ) << (k - i - (unsigned long long) 1);
}
return ret;
}
void fft(std::vector<std::complex<long double>>&a, bool is_reverse = false) {
// 0 1 2 3 4 5 6 7
// 0 2 4 6 1 3 5 7
// 0 4 2 6 1 5 3 7
unsigned long long n = a.size();
unsigned long long k = __builtin_ctz(n);
for(unsigned long long i = 0 ; i < n ; i++) {
unsigned long long j = bitconvert(i, k);
if(i < j) {
std::complex<long double> temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
// 0 1 2 3 4 5 6 7
// 0 2 4 6 / 1 3 5 7
// 0 4 / 2 6 / 1 5 / 3 7
// a[n] = aeven[n] + w[n] * aodd[n]
// a[n + N/2] = aeven[n] - w[n] * odd[n]
// w[n] = exp(2 pi/ s )
for(unsigned long long s = 2 ; s <= n ; s *= 2) {
std::vector<std::complex<long double>> w(s/2);
for(int i = 0 ; i < s/2 ; i++) {
long double t = (long double)2 * PI * i / (long double)s;
if(is_reverse) {
t *= (long double) -1;
}
w[i] = std::complex<long double> (cos(t), sin(t));
}
for(unsigned long long i = 0 ; i < n ; i += s) {
for(unsigned long long j = 0 ; j < s/2 ; j++) {
std::complex<long double> odd = a[i + j + s/2];
std::complex<long double> even = a[i + j];
a[i + j] = even + w[j] * odd;
a[i + j + s/2] = even - w[j] * odd;
}
}
}
if(is_reverse) {
for(unsigned long long i = 0 ; i < n ; i++) {
a[i] /= (long double) n;
}
}
}
void convolution (std::vector<std::complex<long double>> &a, std::vector<std::complex<long double>> &b) {
fft(a);
fft(b);
for(unsigned long long i = 0 ; i < a.size() ; i++) {
a[i] *= b[i];
}
fft(a, true);
}