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tools.py
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'''
#####图片的拼接
import os
from PIL import Image
def concatenate_images(image1_path, image2_path, output_path):
# 打开两张图片
image1 = Image.open(image1_path)
image2 = Image.open(image2_path)
# 确保两张图片的高度一致，可以选择是水平或垂直拼接，这里我们水平拼接
if image1.height != image2.height:
image2 = image2.resize((int(image2.width * image1.height / image2.height), image1.height))
# 创建一个新的图片，宽度是两张图片宽度的总和，高度是两张图片的高度（这里相同）
new_image = Image.new('RGB', (image1.width + image2.width, image1.height))
# 将两张图片粘贴到新图片上
new_image.paste(image1, (0, 0))
new_image.paste(image2, (image1.width, 0))
# 保存新图片
new_image.save(output_path)
def process_images(input_dir, output_dir):
# 确保输出目录存在
if not os.path.exists(output_dir):
os.makedirs(output_dir)
# 遍历输入目录下的所有文件
for filename in os.listdir(input_dir):
if filename.endswith('.png') and 'semantic' not in filename:
base_name = os.path.splitext(filename)[0]
semantic_filename = f"{base_name}_semantic.png"
semantic_filepath = os.path.join(input_dir, semantic_filename)
# 检查是否存在相应的 '_semantic' 文件
if os.path.exists(semantic_filepath):
original_filepath = os.path.join(input_dir, filename)
output_filepath = os.path.join(output_dir, f"{base_name}_combined.png")
# 拼接图片并保存到输出目录
concatenate_images(original_filepath, semantic_filepath, output_filepath)
print(f"Created: {output_filepath}")
# 使用示例
# ['bicycle', 'chair', 'giraffe', 'rifle', 'shoulder_bag']
input_directory = "C:/Users/12147/Desktop/objaverse/vis_alignCourse/shoulder_bag" # 输入目录
output_directory = "imgs/vis_alignCourse/shoulder_bag" # 输出目录
process_images(input_directory, output_directory)
'''
'''# 视频的拼接
import os
from moviepy.editor import VideoFileClip, clips_array
def concatenate_videos_side_by_side(video1_path, video2_path, output_path):
# 打开两个视频文件
video1 = VideoFileClip(video1_path)
video2 = VideoFileClip(video2_path)
# 确保两个视频的高度一致，如果不一致，可以选择缩放较小的视频
if video1.size[1] != video2.size[1]:
video2 = video2.resize(height=video1.size[1])
# 将两个视频水平拼接在一起（一个在左边，一个在右边）
final_video = clips_array([[video1, video2]])
# 将拼接后的新视频保存
final_video.write_videofile(output_path, codec="libx264", fps=24)
def process_videos(input_dir, output_dir):
# 确保输出目录存在
if not os.path.exists(output_dir):
os.makedirs(output_dir)
# 遍历输入目录下的所有文件
for filename in os.listdir(input_dir):
if filename.endswith('.mp4') and 'semantic' not in filename:
base_name = os.path.splitext(filename)[0]
semantic_filename = f"{base_name}_semantic.mp4"
semantic_filepath = os.path.join(input_dir, semantic_filename)
# 检查是否存在相应的 '_semantic' 文件
if os.path.exists(semantic_filepath):
original_filepath = os.path.join(input_dir, filename)
output_filepath = os.path.join(output_dir, f"{base_name}_combined.mp4")
# 拼接视频并保存到输出目录
concatenate_videos_side_by_side(original_filepath, semantic_filepath, output_filepath)
print(f"Created: {output_filepath}")
# 使用示例
# ['bicycle', 'chair', 'giraffe', 'rifle', 'shoulder_bag']
input_directory = "C:/Users/12147/Desktop/objaverse/vis_alignCourse/shoulder_bag" # 输入目录
output_directory = "imgs/vis_alignCourse/shoulder_bag" # 输出目录
process_videos(input_directory, output_directory)'''
import os
import re
def remap_filenames(directory):
# 获取目录下所有文件名
files = os.listdir(directory)
# 过滤掉包含'temp_ins'的
files = [filename for filename in files if 'temp_ins_' not in filename]
# 用于存储新的文件名与数字的映射
number_mapping = {}
counter = 0
# 遍历所有文件
for filename in files:
# 分离文件名和扩展名
name, ext = os.path.splitext(filename)
# 查找所有包含 _数字 的部分
matches = re.findall(r'_(\d+)', name)
# 如果有匹配项，进行映射
if matches:
for match in matches:
if match not in number_mapping:
number_mapping[match] = counter
counter += 1
# 替换原文件名中的 _数字_ 为新的数字
name = name.replace(f'_{match}', f'_{number_mapping[match]}')
# 创建新的文件名
new_name = name + ext
# 修改文件的名称
original_path = os.path.join(directory, filename)
new_path = os.path.join(directory, new_name)
if original_path != new_path: # 避免重命名为相同的文件名
os.rename(original_path, new_path)
print(f'Renamed: {original_path} -> {new_path}')
return
# 使用示例
cates = ['bicycle', 'chair', 'giraffe', 'rifle', 'shoulder_bag']
for cate in cates:
directory_path = 'imgs/vis_alignCourse/' + cate # 替换为要处理的目录路径
remap_filenames(directory_path)