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Weights from working groups in n(z) estimation #3

@joezuntz

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@joezuntz

When the WGs pass you a collection of galaxies we've selected that we'd like the n(z) for, we may also need to pass you a weight per galaxy. The perfect n(z) would then be a weighted histogram of the true z values for each object.

I just wanted to make sure that was on your radar!

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