How to get req.query req.params if we dont know the shape

[fbritoferreira]

I have an app where we want to accept a wide number of params and query and pull it all together as a object.

I was wandering if i we could use input: z.record(z.string(), z.string()) it would accept them and pull those together

Existing Middleware

       const options = {};

        Object.keys(req.query).forEach(param => options[param] = req.query[param]);
        Object.keys(req.params).forEach(param => options[param] = req.params[param]);

        req.opts = options;

[RobinTail]

Hello @fbritoferreira ,

request properties are combined and into a single object that is being validated against input schema, which has to be z.object.
However, you can easily enable unknown properties on that schema by utilizing .passthrough() method.

Check out this example:

https://github.com/RobinTail/express-zod-api/blob/master/example/endpoints/upload-avatar.ts#L18

Another advice could be making your z.record schema a property inside the input schema object, like this:

z.object({ 
  params: z.record(
    z.string(), z.string(),
  )
})

I hope this would help you

[RobinTail]

I forget to mention, that .passthrough() on schema is only available for Endpoint.
If you need it for Middleware, then you solution with manual examination of req.body and req.params and putting them into options might be the best one.

However, I'd still recommend using a property inside of options for all your unknown inputs, @fbritoferreira