Smart Keypad - I Solution Added

Author: akashmodak97

Hacker Blocks/Smart Keypad - I.cpp

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+/* Hacker Blocks */
+/* Title - Smart Keypad - I */
+/* Created By - Akash Modak */
+/* Date - 14/07/2020 */
+
+// You will be given a numeric string S. Print all the possible codes for S.
+
+// Following vector contains the codes corresponding to the digits mapped.
+
+// string table[] = { " ", ".+@$", "abc", "def", "ghi", "jkl" , "mno", "pqrs" , "tuv", "wxyz" };
+
+// For example, string corresponding to 0 is " " and 1 is ".+@$"
+
+// Input Format
+// A single string containing numbers only.
+
+// Constraints
+// length of string <= 10
+
+// Output Format
+// All possible codes one per line in the following order.
+
+// The letter that appears first in the code should come first
+
+// Sample Input
+// 12
+// Sample Output
+// .a
+// .b
+// .c
+// +a
+// +b
+// +c
+// @a
+// @b
+// @c
+// $a
+// $b
+// $c
+// Explanation
+// For code 1 the corresponding string is .+@$ and abc corresponds to code 2.
+
+#include<iostream>
+using namespace std;
+string table[] = { " ", ".+@$", "abc", "def", "ghi", "jkl" , "mno", "pqrs" , "tuv", "wxyz" };
+void generate(char *inp,int i,int j,char *out){
+	if(inp[i]=='\0'){
+		out[j]='\0';
+		cout<<out<<endl;
+		return;
+	}
+
+	int key = inp[i] - '0';
+	// if(key==0)
+	// generate(inp,i+1,j,out);
+	for(int k=0;table[key][k]!='\0';k++){
+		out[j]=table[key][k];
+		generate(inp,i+1,j+1,out);
+	}
+	return;
+}
+int main() {
+	
+	char inp[100],out[1000];
+	cin>>inp;
+	generate(inp,0,0,out);
+	return 0;
+}