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提供一个思路,可以自定义一个后处理 使用 dagre 布局后,算法会输出节点的位置与边的控制点(此处为控制点 1 和控制点 2)。如果想要使用正交边进行连线,情况会比较简单,只存在拐点 1 和拐点 2 两种情况,再进行碰撞检测并选择适合的拐点即可 ![]() |
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运行代码的链接
![image](https://private-user-images.githubusercontent.com/66106169/380002300-1d9c47d4-80a3-4ec5-9502-d76961aad8bd.png?jwt=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.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.siKDZIoOuWCMQe7FeRSVO31zx1NT9g6f0HrQx13qaC0)
想要实现红色箭头的效果:
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