LeetCode Records - Question 1362 Closest Divisors Attempt 1: Use Math.sqrt() to find the divisors class Solution { public int[] closestDivisors(int num) { int[] divisors1 = getDivisors(num + 1); int[] divisors2 = getDivisors(num + 2); if (divisors1[1] - divisors1[0] <= divisors2[1] - divisors2[0]) { return divisors1; } else { return divisors2; } } private int[] getDivisors(int num) { int divisor = (int)Math.sqrt(num); for (int i = divisor; i >= 2; i--) { if (num % i == 0) { return new int[]{ i, num / i }; } } return new int[]{ 1, num }; } } Runtime: 6 ms (Beats: 76.67%) Memory: 40.89 MB (Beats: 79.46%)