1507. Reformat Date.cpp

Given a date string in the form Day Month Year, where:

Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
Year is in the range [1900, 2100].
Convert the date string to the format YYYY-MM-DD, where:

YYYY denotes the 4 digit year.
MM denotes the 2 digit month.
DD denotes the 2 digit day.


Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"
Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"
Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"


Constraints:

The given dates are guaranteed to be valid, so no error handling is necessary.







class Solution {
public:
    string reformatDate(string date) {
        stringstream ss(date);
        int day, month, year;
        string res, sday, smonth, syear;

        ss>>day;
        ss>>smonth;
        ss>>smonth;
        ss>>year;

        vector<string> v {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

        res+=to_string(year);

        for(int i=0;i<v.size();i++){
            if(v[i]==smonth){
                month=i+1;
                break;
            }
        }

        if(month<10){
            res+="-0"+to_string(month)+"-";
        } else res+="-"+to_string(month)+"-";

        if(day<10){
            res+="0"+to_string(day);
        } else res+=to_string(day);

        return res;


    }
};