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2D-Array-Hourglass.py
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#!/bin/python3
import math
import os
import random
import re
import sys
# PROBLEM: Given a 2D Array (6x6), return the max hourglass sum
# ==== EXAMPLE PROBLEM ======:
# INPUT:
# arr = [
# [1, 1, 1, 0, 0, 0],
# [0, 1, 0, 0, 0, 0],
# [1, 1, 1, 0, 0, 0],
# [0, 0, 2, 4, 4, 0],
# [0, 0, 0, 2, 0, 0],
# [0, 0, 1, 2, 4, 0]
# ]
# ---- GRAPHICAL REPRESENTATION ---- #
# ==== COLUMNS ==== #
# 0 1 2 3 4 5
# ROW 0 | 1 1 1 0 0 0
# ROW 1 | 0 1 0 0 0 0
# ROW 2 | 1 1 1 0 0 0
# ROW 3 | 0 0 2 4 4 0
# ROW 4 | 0 0 0 2 0 0
# ROW 5 | 0 0 1 2 4 0
# APPROACH:
# (1) SUBSET THE MATRIX TO GET HOURGLASS CELLS (7)
# --- HOURGLASS PATTERN --- #
# a b c
# d
# e f g
# === HOURGLASS #1 === #
# 1 1 1
# 1
# 1 1 1
# a -> arr[0][1] = 1
# b -> arr[0][2] = 1
# c -> arr[0][3] = 1
# d -> arr[1][2] = 1
# e -> arr[2][1] = 1
# f -> arr[2][2] = 1
# g -> arr[2][3] = 1
# --- HOURGLASS #1 SUM --- #
# -> sum(hourglass) = 7
# === HOURGLASS #2 === #
# 1 1 0
# 0
# 1 1 0
# a -> arr[0][0] = 1 ** i=0, j=0 **
# b -> arr[0][1] = 1 ** i=0, j=1**
# c -> arr[0][2] = 0
# d -> arr[1][1] = 0
# e -> arr[2][0] = 1
# f -> arr[2][1] = 1
# g -> arr[2][2] = 0
# --- HOURGLASS #2 SUM --- #
# -> sum(hourglass) = 4
# APPROACH:
# == VARIABLES == #
# max_sum = 0
# STEP 1: Subset array to get hourglass pattern (x16)
# STEP 2: Calculate sum of each hourglass [curr_sum]
# STEP 3: Compare the max_sum to the curr_sum
def hourglassSum(arr):
# Write your code here
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
arr = []
for _ in range(6):
arr.append(list(map(int, input().rstrip().split())))
result = hourglassSum(arr)
fptr.write(str(result) + '\n')
fptr.close()