Simple python socket server

Author: duboviy

server.py

@@ -0,0 +1,42 @@
+import socket
+import sys
+
+HOST = ''  # interface
+PORT = 8888  # port
+
+s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
+print('Socket created')
+
+# Bind socket to local host and port
+try:
+    s.bind((HOST, PORT))
+except socket.error as msg:
+    print('Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1])
+    sys.exit()
+
+print('Socket bind complete')
+
+# Start listening on socket
+s.listen(10)
+print('Socket now listening')
+
+# now keep talking with the client
+while 1:
+    conn, addr = s.accept()
+    print('Connected with ' + addr[0] + ':' + str(addr[1]))
+    conn.send(b'Welcome to the server. Type something and hit enter\n')
+    while True:
+        data = conn.recv(1024)
+        reply = 'Reply text\n'
+        if not data:
+            break
+
+        conn.sendall(bytes(reply, 'utf-8'))
+
+    conn.close()
+
+s.close()
+
+
+# To test just use:
+# >>> telnet localhost 8888