Chapter 4: org.hibernate.exception.SQLGrammarException: could not prepare statement

[JerryFinn]

This problem is because the table user, "user" is a reserve word, so if when you submit to register a user you get the above error. The solution has been noted in the post in a later version of this book by user https://github.com/Dieblich
habuma/spring-in-action-6-samples#7

To repeat here, where I first found it, the solution is ...
<<
Spring cannot create the data-table.

I solved this issue with an annotation for the table:

import javax.persistence.Table;
...
@table(name="TACO_USER")
public class User implements UserDetails {
...

This worked for me too.