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‎04. Patterns 2/1. Inverted triangle.ipynb

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"****\n",
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"***\n",
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"**\n",
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"*"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 9,
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"metadata": {
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"scrolled": true
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"4\n",
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"****\n",
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"***\n",
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"**\n",
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"*\n"
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]
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}
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],
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"source": [
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"n = int(input())\n",
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"i = 1\n",
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"while i<=n:\n",
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" j = 1\n",
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" while j <= n-i+1:\n",
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" print('*',end='') \n",
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" j = j +1\n",
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" print() \n",
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" i = i+1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 5,
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"metadata": {
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"scrolled": true
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"4\n",
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"1111\n",
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"000\n",
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"11\n",
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"0\n"
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]
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}
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],
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"source": [
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"n = int(input())\n",
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"i = 1\n",
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"while i <= n:\n",
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" j =1\n",
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" while j<= n-i+1:\n",
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" print(i%2,end='')\n",
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" j = j+1\n",
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" print()\n",
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" i = i + 1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 26,
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"metadata": {
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"scrolled": true
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"4\n",
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"A\n",
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"BB\n",
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"CCC\n",
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"DDDD\n"
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]
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}
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],
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"source": [
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"n = int(input())\n",
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"\n",
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"i = 1\n",
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"\n",
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"while i <= n:\n",
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" \n",
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" char = chr(ord('A') + i - 1)\n",
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" \n",
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" j = 1\n",
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" \n",
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" while j <= i:\n",
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" print(char, end=\"\")\n",
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" j += 1\n",
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" \n",
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" print()\n",
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" i +=1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 1,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"4\n",
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"1\n",
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"11\n",
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"121\n",
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"1221\n"
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]
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}
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],
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"source": [
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"n=int(input())\n",
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"i=1\n",
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"while i<=n:\n",
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" j=1\n",
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" while j<=i:\n",
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" if i==1:\n",
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" print('1',end='')\n",
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" elif j==1 or i==j:\n",
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" print('1',end='')\n",
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" else:\n",
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" print('2',end='')\n",
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" j=j+1\n",
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" print()\n",
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" i=i+1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"metadata": {
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"scrolled": true
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"4\n",
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"D\n",
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"CD\n",
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"BCD\n",
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"ABCD\n"
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]
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}
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],
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"source": [
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"n = int(input())\n",
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"i = n\n",
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"while i >= 1:\n",
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" j = i\n",
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" while j<=n:\n",
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" print(chr(ord(\"A\")+j-1),end=\"\")\n",
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" j = j + 1\n",
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" print()\n",
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" i = i - 1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 1,
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"metadata": {
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"scrolled": true
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"4\n",
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"1234\n",
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"123\n",
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"12\n",
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"1\n"
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]
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}
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],
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"source": [
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"n = int(input())\n",
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"i = 1\n",
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"while i<=n:\n",
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" j = 1\n",
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" p =1\n",
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" while j <= n-i+1:\n",
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" print(p,end='') \n",
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" j = j +1\n",
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" p =p+1\n",
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" print() \n",
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" i = i+1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 18,
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"metadata": {
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"scrolled": true
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"5\n",
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"1 2 3 4 5 \n",
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"11 12 13 14 15 \n",
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"21 22 23 24 25 \n",
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"16 17 18 19 20 \n",
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"6 7 8 9 10 \n"
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]
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}
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],
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"source": [
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"n=int(input())\n",
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"s=1\n",
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"for i in range (1,n+1):\n",
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" for j in range(s,s+n):\n",
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" print(j ,end=\" \")\n",
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" print()\n",
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" if (i==((n+1)//2)):\n",
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" if n%2!=0:\n",
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" s=n*(n-2)+1\n",
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" else:\n",
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" s=n*(n-1)+1\n",
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" continue\n",
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" if (i>(n+1)//2):\n",
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" s=s-2*n\n",
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" else:\n",
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" s=s+2*n"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.5"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

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