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2-addTwoNumbers.js
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// From LeetCode
// You are given two non-empty linked lists representing two non-negative integers.
// The digits are stored in reverse order and each of their nodes contain a single digit.
// Add the two numbers and return it as a linked list.
// You may assume the two numbers do not contain any leading zero, except the number 0 itself.
// @param {ListNode} l1
// @param {ListNode} l2
// @return {ListNode}
function ListNode(val, next) {
this.val = val === undefined ? 0 : val;
this.next = next === undefined ? null : next;
}
// Create Linked lists from numbers
createLinkedListNumber = function (number) {
const remainder = number % 10;
const division = Math.floor(number / 10);
if (division !== 0) {
return new ListNode(remainder, createLinkedListNumber(division));
} else {
return new ListNode(remainder, undefined);
}
};
printLinkedListNumber = function (linkedListNumber) {
let num = linkedListNumber;
let nextNum = num.next;
while (true) {
console.log(num.val);
if (nextNum === null) {
break;
}
num = nextNum;
nextNum = num.next;
}
};
// Solution /////////////////////////
var addTwoNumbers = function (l1, l2, carryover = 0) {
console.log(`Carryover is: ${carryover}`);
if (l1 === null && l2 === null) {
if (carryover === 1) {
return new ListNode(1, null);
}
return null;
} else if (l1 === null) {
if (l2.val + carryover >= 10) {
return new ListNode(
(l2.val + carryover) % 10,
addTwoNumbers(null, l2.next, 1)
);
}
return new ListNode(l2.val + carryover, addTwoNumbers(null, l2.next));
} else if (l2 === null) {
if (l1.val + carryover >= 10) {
return new ListNode(
(l1.val + carryover) % 10,
addTwoNumbers(l1.next, null, 1)
);
}
return new ListNode(l1.val + carryover, addTwoNumbers(l1.next, null));
} else {
const sum = l1.val + l2.val + carryover;
if (sum >= 10) {
return new ListNode(sum % 10, addTwoNumbers(l1.next, l2.next, 1));
}
return new ListNode(sum, addTwoNumbers(l1.next, l2.next));
}
};
const linkedListNumber1 = createLinkedListNumber(999);
const linkedListNumber2 = createLinkedListNumber(1);
printLinkedListNumber(addTwoNumbers(linkedListNumber1, linkedListNumber2));