From 4ef5d553d4149dfaacaae46b8b9a1b531cfc6186 Mon Sep 17 00:00:00 2001
From: pfatheddin <156558883+pfatheddin@users.noreply.github.com>
Date: Sun, 24 Mar 2024 18:02:59 -0400
Subject: [PATCH] Update meanValueTheorem5.tex

https://ximera.osu.edu/mooculus/meanValueTheorem/exercises/exerciseList/meanValueTheorem/exercises/meanValueTheorem5

Took out the hint. No need to give the average rate formula. They are likely to know it by now.
---
 meanValueTheorem/exercises/meanValueTheorem5.tex | 9 +--------
 1 file changed, 1 insertion(+), 8 deletions(-)

diff --git a/meanValueTheorem/exercises/meanValueTheorem5.tex b/meanValueTheorem/exercises/meanValueTheorem5.tex
index 33ceb5d3d..4f1147f07 100644
--- a/meanValueTheorem/exercises/meanValueTheorem5.tex
+++ b/meanValueTheorem/exercises/meanValueTheorem5.tex
@@ -34,13 +34,6 @@
 Compute the average velocity of the object during the time interval $[0,4]$.
 
 
-\begin{hint}
-Recall, the average velocity during the time interval $[0,4]$ is given by the expression 
-\[
-\frac{s(\answer{4})-s(\answer{0})}{4-0}
-\]
-\end{hint}
-
 
 The average velocity of the object during the time interval $[0,4]$ is $\answer{20}$ m/s.
 
@@ -57,4 +50,4 @@
 
 This means that at the time $t=c$ the \textbf{instantaneous velocity} of the object is equal to the \textbf{average velocity} of the object during the time interval $[0,4]$.
 \end{exercise}
-\end{document}
\ No newline at end of file
+\end{document}