Nowadays math.sqrt() is fast than ** 0.5 #42

DimitriPapadopoulos · 2023-04-06T14:55:31Z

While ** 0.5 might have been faster in Python 2, math.sqrt() is faster in Python 3.

https://stackoverflow.com/questions/20226747/is-there-any-advantage-using-math-sqrtnum-over-num0-5-in-python
https://stackoverflow.com/questions/327002/which-is-faster-in-python-x-5-or-math-sqrtx

Fixes #30.

While `** 0.5` might have been faster in Python 2, `math.sqrt()` is faster in Python 3. https://stackoverflow.com/questions/20226747/is-there-any-advantage-using-math-sqrtnum-over-num0-5-in-python

Nowadays math.sqrt() is fast than ** 0.5

72a1293

While `** 0.5` might have been faster in Python 2, `math.sqrt()` is faster in Python 3. https://stackoverflow.com/questions/20226747/is-there-any-advantage-using-math-sqrtnum-over-num0-5-in-python

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Nowadays math.sqrt() is fast than ** 0.5 #42

Nowadays math.sqrt() is fast than ** 0.5 #42

DimitriPapadopoulos commented Apr 6, 2023

Nowadays math.sqrt() is fast than ** 0.5 #42

Are you sure you want to change the base?

Nowadays math.sqrt() is fast than ** 0.5 #42

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DimitriPapadopoulos commented Apr 6, 2023