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K-diffPairsInAnArray532.cpp
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66 lines (66 loc) · 1.78 KB
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class Solution {
public:
bool bs (vector<int>& nums, int target, int index) {
int left = 0, right = nums.size()-1, mid;
while (left <= right) {
mid = (left+right)/2;
if (nums[mid] == target) {
if (mid != index) {
return true;
} else {
if (mid+1 < nums.size() && nums[mid+1] == target) {
return true;
} else if (mid > 0 && nums[mid-1] == target) {
return true;
} else {
return false;
}
}
} else if (nums[mid] < target) {
left = mid+1;
} else {
right = mid-1;
}
}
return false;
}
int findPairs(vector<int>& nums, int k) {
if (k < 0 || nums.size() == 0) return 0;
sort(nums.begin(), nums.end());
int prev = nums[0]-1, ans = 0;
for (int i = 0; i < nums.size(); i++) {
if (prev != nums[i]) {
if (bs(nums, nums[i]+k, i)) ans++;
}
prev = nums[i];
}
return ans;
}
};
//the fatest solution
using namespace std;
auto __ =[]()
{
std::ios::sync_with_stdio(false);
cin.tie(nullptr);
return nullptr;
}();
class Solution {
public:
int findPairs(vector<int>& nums, int k) {
if (k < 0 || nums.size() < 1) {
return 0;
}
int result = 0;
std::unordered_map<int, int> m;
for (int n:nums) {
m[n]++;
}
for (auto item : m) {
if ((k == 0 && item.second > 1)|| (k != 0 && m.count(item.first + k))) {
result++;
}
}
return result;
}
};