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lfos[LfoShape::square].initialise ([] (T x) { return x < 0 ? T (0) : T (1); });
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// TODO: because we don't give the lookupTableNumPoints parameter to the lfo, we're not building a lookup table, and we can't because of the state logic.
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// TODO #63: because we don't give the lookupTableNumPoints parameter to the lfo, we're not building a lookup table, and we can't because of the state logic.
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// So this means this function takes longer than the other ones. Which is only called once per buffer, so probably not a big deal, but the whole logic is kinda
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