Skip to content

Fix deserialization method for PersonInfo #324

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
wants to merge 1 commit into
base: main
Choose a base branch
from
Open

Fix deserialization method for PersonInfo #324

Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
2 changes: 1 addition & 1 deletion agent-framework/tutorials/agents/structured-output.md
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -104,7 +104,7 @@ var response = await agent.RunAsync("Please provide information about John Smith
The agent response can then be deserialized into the `PersonInfo` class using the `Deserialize<T>` method on the response object.

```csharp
var personInfo = response.Deserialize<PersonInfo>(JsonSerializerOptions.Web);
Copy link
Collaborator

@westey-m westey-m Nov 13, 2025

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

@marknhenry, this code looks correct to me. Isn't AgentRunResponse.Deserialize working for you?

Copy link
Author

@marknhenry marknhenry Nov 13, 2025

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

No it's not running for me. The issue is in JsonSerializerOptions.Web.

Copy link
Collaborator

@westey-m westey-m Nov 13, 2025

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

What is the failure you are seeing?

var personInfo = JsonSerializer.Deserialize<PersonInfo>(response.ToString(), new JsonSerializerOptions(JsonSerializerDefaults.Web));
Console.WriteLine($"Name: {personInfo.Name}, Age: {personInfo.Age}, Occupation: {personInfo.Occupation}");
```

Expand Down