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new code #133
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Pull Request Overview
This PR introduces example code into daliadmin.cpp that dynamically allocates an unsigned integer, performs two summation loops, and prints results.
- Adds dynamic allocation and initialization of
myvariablename - Implements two summation loops (linear and nested) and prints results
- Does not clean up allocated memory
Comments suppressed due to low confidence (1)
dali/daliadmin/daliadmin.cpp:151
- [nitpick] The variable name
myvariablenameis ambiguous and doesn’t follow camelCase conventions. Consider a clearer name likemaxIterationsorlimit.
unsigned *myvariablename = new unsigned;
| unsigned *myvariablename = new unsigned; | ||
| *myvariablename = 10000; | ||
| printf("%d\n", *myvariablename); | ||
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|
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| unsigned __int64 sum = 0; | ||
| // sum up all the numbers from 0 to 9999 | ||
| for (unsigned x=0; x<*myvariablename; x++) | ||
| { | ||
| sum += x; | ||
| } | ||
| printf("%llu\n", sum); | ||
| sum = 0; | ||
| // sum up all the numbers from 0 to 9999 N times | ||
| for (unsigned x=0; x<*myvariablename; x++) | ||
| { | ||
| for (unsigned y=0; y<*myvariablename; y++) |
Copilot
AI
Jul 14, 2025
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This dynamically allocated unsigned is never freed, causing a memory leak. Consider using a stack variable or managing its lifetime to ensure delete is called.
| unsigned *myvariablename = new unsigned; | |
| *myvariablename = 10000; | |
| printf("%d\n", *myvariablename); | |
| unsigned __int64 sum = 0; | |
| // sum up all the numbers from 0 to 9999 | |
| for (unsigned x=0; x<*myvariablename; x++) | |
| { | |
| sum += x; | |
| } | |
| printf("%llu\n", sum); | |
| sum = 0; | |
| // sum up all the numbers from 0 to 9999 N times | |
| for (unsigned x=0; x<*myvariablename; x++) | |
| { | |
| for (unsigned y=0; y<*myvariablename; y++) | |
| unsigned myvariablename; | |
| myvariablename = 10000; | |
| printf("%d\n", myvariablename); | |
| unsigned __int64 sum = 0; | |
| // sum up all the numbers from 0 to 9999 | |
| for (unsigned x=0; x<myvariablename; x++) | |
| { | |
| sum += x; | |
| } | |
| printf("%llu\n", sum); | |
| sum = 0; | |
| // sum up all the numbers from 0 to 9999 N times | |
| for (unsigned x=0; x<myvariablename; x++) | |
| { | |
| for (unsigned y=0; y<myvariablename; y++) |
| unsigned *myvariablename = new unsigned; | ||
| *myvariablename = 10000; | ||
| printf("%d\n", *myvariablename); | ||
|
|
||
| unsigned __int64 sum = 0; | ||
| // sum up all the numbers from 0 to 9999 | ||
| for (unsigned x=0; x<*myvariablename; x++) | ||
| { | ||
| sum += x; | ||
| } | ||
| printf("%llu\n", sum); | ||
| sum = 0; | ||
| // sum up all the numbers from 0 to 9999 N times | ||
| for (unsigned x=0; x<*myvariablename; x++) | ||
| { | ||
| for (unsigned y=0; y<*myvariablename; y++) |
Copilot
AI
Jul 14, 2025
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[nitpick] Instead of dynamically allocating a single unsigned, declare it as a local variable (e.g., unsigned myVariableName = 10000;).
| unsigned *myvariablename = new unsigned; | |
| *myvariablename = 10000; | |
| printf("%d\n", *myvariablename); | |
| unsigned __int64 sum = 0; | |
| // sum up all the numbers from 0 to 9999 | |
| for (unsigned x=0; x<*myvariablename; x++) | |
| { | |
| sum += x; | |
| } | |
| printf("%llu\n", sum); | |
| sum = 0; | |
| // sum up all the numbers from 0 to 9999 N times | |
| for (unsigned x=0; x<*myvariablename; x++) | |
| { | |
| for (unsigned y=0; y<*myvariablename; y++) | |
| unsigned myvariablename = 10000; | |
| printf("%d\n", myvariablename); | |
| unsigned __int64 sum = 0; | |
| // sum up all the numbers from 0 to 9999 | |
| for (unsigned x=0; x<myvariablename; x++) | |
| { | |
| sum += x; | |
| } | |
| printf("%llu\n", sum); | |
| sum = 0; | |
| // sum up all the numbers from 0 to 9999 N times | |
| for (unsigned x=0; x<myvariablename; x++) | |
| { | |
| for (unsigned y=0; y<myvariablename; y++) |
|
|
||
| unsigned *myvariablename = new unsigned; | ||
| *myvariablename = 10000; | ||
| printf("%d\n", *myvariablename); |
Copilot
AI
Jul 14, 2025
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The format specifier %d is for signed integers; for an unsigned value use %u to ensure correct output and defined behavior.
| printf("%d\n", *myvariablename); | |
| printf("%u\n", *myvariablename); |
| { | ||
| sum += x; | ||
| } | ||
| printf("%llu\n", sum); |
Copilot
AI
Jul 14, 2025
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Using %llu assumes unsigned long long; for portability with unsigned __int64, consider using the PRIu64 macro or matching the exact type’s specifier.
| for (unsigned x=0; x<*myvariablename; x++) | ||
| { | ||
| for (unsigned y=0; y<*myvariablename; y++) | ||
| { | ||
| // nested loop | ||
| sum += x; | ||
| } | ||
| } | ||
| printf("%llu\n", sum); |
Copilot
AI
Jul 14, 2025
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This nested loop results in O(n²) complexity and may impact performance for large values. Consider whether the double summation is necessary or can be optimized.
| for (unsigned x=0; x<*myvariablename; x++) | |
| { | |
| for (unsigned y=0; y<*myvariablename; y++) | |
| { | |
| // nested loop | |
| sum += x; | |
| } | |
| } | |
| printf("%llu\n", sum); | |
| // Calculate the sum directly using a mathematical formula | |
| sum = *myvariablename * ((*myvariablename - 1) * *myvariablename / 2); | |
| // The formula computes the sum of x repeated *myvariablename times for all x from 0 to *myvariablename - 1 | |
| printf("%llu\n", sum); | |
| printf("%llu\n", sum); |
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