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Update LinearApproximations7.tex #972

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6 changes: 3 additions & 3 deletions linearApproximation/exercises/LinearApproximations7.tex
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Expand Up @@ -28,9 +28,9 @@
\d{N} = \frac{\answer{2000000}e^{-0.1t}}{\left(1+100e^{-0.1t}\right)^2}\d{t}.
\]

Assuming that 45 days have passed since the outbreak started, we use the above formula to estimate the number of people (rounded to the nearest 1 person) that will fall sick in the next day. That number is approximately $\answer{4986}$.
After 45 days since the outbreak started, we use the above formula to estimate the number of people (rounded to the nearest 1 person) that will fall sick on the next day. That number is approximately $\answer{4986}$.

Assuming that 100 days have passed since the outbreak started, we use the above formula to estimate the number of people (rounded to the nearest 1 person) that will fall sick in the next day. That number is approximately $\answer{90}$.
After 100 days since the outbreak started, we use the above formula to estimate the number of people (rounded to the nearest 1 person) that will fall sick on the next day. That number is approximately $\answer{90}$.

\end{exercise}
\end{document}
\end{document}